You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t^2 + 541. What is the height of the rock after 2 seconds?
For this case we have the following equation: [tex]h = -16t ^ 2 + 541
[/tex] To answer the question, what we must do is evaluate the function for t = 2. We have then: [tex]h = -16 (2) ^ 2 + 541
[/tex] Rewriting we have: [tex]h = -16 (4) + 541
h = -64 + 541
h = 477 feet[/tex] Answer: The height of the rock after 2 seconds is: [tex]h = 477 feet[/tex]
