let x-----------> the length of a rectangle y-----------> the width of a rectangle
we know that area of a rectangle =length*width area=55 mi² 55=x*y--------> equation 1 y=x-6-------> equation 2 substitute equation 2 in equation 1 55=x*[x-6]------> 55=x²-6x----------> x²-6x-55=0
using a graph tool-----> to resolve the second order equation see the attached figure
the solution is x=11 mi y=x-6-----> y=11-6-----> y=5 mi
the answer is the length of a rectangle is 11 miles the width of a rectangle is 5 miles
